The answer:
bn = (1/2pi) [(3/(1-3n))sin(((1-3n)/3)x) - (3/(1+3n))sin(((1+3n)/3)x)]
is my attempt in integrating the bn coefficient of the Fourier series of sin(x/3) as a0 and an are both equal to zero after using the .5[cos(A-B)-cos(A+B)]=sinAsinB formula.
However the values I get...
Homework Statement
Let f be the 2 periodic function defined on [−pi,pi ) by
f(x) = sin(x/3)
Find the Fourier coefficients of f.
Homework Equations
.5[cos(A-B)-cos(A+B)]=sinAsinB
The Attempt at a Solution
After much work using trigonometry and integration by parts I have...