Recent content by zsviben

Hi, Do you mean under the rate of change of a circle the change of radius? I do not mean such a thing, trajectory is fixed, and the derivative only means the unit vector in the direction of movement (velocity unit vector).

Hi, is the force in the radial direction ? I put one calculation where the force is in the radial direction and has the same origin as the circle (see q.pdf). Yes, q is the length on a circle (q goes from 0 to 2πR and above). q/R is then the angle in radians. Bye

Hi, I just wanted to see if this helps somehow? (I played a little, and I do not guarantee that it is 100% correct) Bye

Hi, if the right side of equ is constant, you can solve it easily w = k Tan[k (r+c)] where k = Sqrt[A(V1-V2)+B+C(V1+V2)] and c is the constant of integration what is determined from initial conditions Bye,

Hi, I do not know if you still need the help, but i found it interesting to see the answer :) so from f(x) = x or 4/x+x/2-c = x we have x^2+2cx-8 = 0 or x = p(c) = -c+-sqrt{c^2+8} and since we are only looking for the positive solution we choose p(c) = -c+sqrt{c^2+8}for the interval we choose...