Recent content by zubb999

Ok... So according to what you just said, I should have this at my disposal: TBAy = 60 lb. tanθ = h/15 in. --> θ=tan-1(h/15 in.) If TBA = TBAy x sinθ then TBA = TBAy x sin(tan-1(h/15 in.)) If TBA = TBAx x cosθ then TBA = TBAx x cos(tan-1(h/15 in.)) Right? And then when I bring TBC to put all...

Homework Statement The 60 lb collar "A" is on a friction-less vertical rod and is connect to a 65 lb counterweight "C". Determine the value "h" (which is the height between "A" and "B") for which the system is in equilibrium. Also, find the horizontal force "N" acting on collar "A". Here is a...