A few weeks ago, I saw a post regarding the area under the function xsinxsin2x dx, (x = pi*x/a). After cogitations, I have found the answer:
∫x*Sin(x)*Sin(2x) dx = - xSin(2x)Cos(x) + ∫Cos(x) dx
= Sin(x) - xSin(2x)Cos(x) + C
By assuming u = xsin2x, du =...
OK, I know the solution for cos^3 x dx is sinx - sin^3 x / 3 + C.
And that
you basically solve
integral of cosx*(1-sin^2x) dx. to get it.
but,...
what I don't get is how do you solve cosx*(1-sin^x) dx... is there a trick that I didn't get from the parts formula?
Calculus help please!
Plz help me do the problem below. thanks a lot.
Show that the following integral is CORRECT:
Indefinite Integral of 1/(1-x)^2 dx = x/(1-x)