Gravitational field strength Definition and 54 Threads

Homework Statement a) Find the altitude above the Earth's surface where Earth's gravitational field strength would be two-thirds of its value at the surface. Assume re = 6.371 103 km. __________ km (b) Find the altitude above the Earth's surface where Earth's gravitational field strength...

From the radius (1740 km) and mass (7.36 X 10^22 kg) of the moon, calculate gravitational field strength for this body. g = F/m = F/(7.36X10^22 kg) F = GmM/r^2 = (6.67X10^-11)(7.36X10^22)M/(1740X10^3)^2 What is the big M?

Q: "The Earths radius is 6700km. Show that the magnitude of the gravitational field strength at a height of 350km above the Earth's surface is about 9 N/kg" I got the mass of the Earth which is 5.98E 24 G the constant = 6.67E -11 Formula : g= GM/r² , i can't seem to get 9, am I supposed...

I was just wondering. How come the gravitational field strength of the sun is much larger than the gravitational field strength of the moon at when you calculate both values at Earth's position?