Derivation of the Kinematic Equations

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alexgraham
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A car slows down from 23 m/s to rest in a distance of 85m. what was its acceleration, assumed constant?
a=Δv/Δt x=1/2at^2
i don't know where to start
 
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what is the velocity-displacement formula?
 
in that equation is v the change in velocity?
 
Ignore this post, it was bad advice!
 
Last edited:
okay thanks i guess my teacher messed up
 
I'm sorry, I just gave you some bad advice...ignore my first response.
 
I don't know what I was thinking, but yeah you use (final velocity)^2 = (initial velocity)^2 + 2*a*x and just substitute the stuff you know and solve for a.
 
Does anyone know how to derive V^2=V0^2+2as

Ratch
 
Take the velocity-time equation:
[tex] v = v_{0} + a \, t[/tex]
and the position time equation:
[tex] x = v_{0} \, t + \frac{1}{2} \, a \, t^{2}[/tex]
and eliminate time t.
 
Ratch said:
Does anyone know how to derive V^2=V0^2+2as

Ratch

Work energy theorem
KEv2-KEv0=mas