How does spacetime curvature affect objects at rest on Earth's surface?

[sngtdt]

My question concerns the affect of the curvature of space on a stationary object. I understand that the force of gravity is more accurately described as space curvature. Ie, a massive object like the sun or Earth can be visualized as a bowling ball placed on a rubber sheet, creating a curvature. Objects passing nearby on a straight trajectory will then assume a curved trajectory. I am wondering if the same thing applies to stationary objects on the surface, like a person standing on the earth. How? The model of the bowling ball on a sheet makes it easy to understand the curved path a beam of light will assume passing a massive object. Is there a similar model for stationary objects? Thanks in advance.

 

[Passionflower]

My question concerns the affect of the curvature of space on a stationary object. I understand that the force of gravity is more accurately described as space curvature. Ie, a massive object like the sun or Earth can be visualized as a bowling ball placed on a rubber sheet, creating a curvature. Objects passing nearby on a straight trajectory will then assume a curved trajectory. I am wondering if the same thing applies to stationary objects on the surface, like a person standing on the earth. How? The model of the bowling ball on a sheet makes it easy to understand the curved path a beam of light will assume passing a massive object. Is there a similar model for stationary objects? Thanks in advance.

Both the stationary and free falling object will encounter inertial acceleration, however the stationary object compensates this inertial acceleration with a proper acceleration in the opposite direction.

 

[Dale]

I understand that the force of gravity is more accurately described as spacetime curvature.

I have corrected the word "space" in your statement above. General relativity uses curved spacetime to describe gravitation, not just curved space. Are you familiar with the concept of "spacetime"?