Is It Possible to Prove Logarithms Using Equations?

  • Thread starter Thread starter TheMathNoob
  • Start date Start date
  • Tags Tags
    Logarithms Proof
Click For Summary

Homework Help Overview

The discussion revolves around proving the equation xlogby = ylogbx, which involves logarithmic properties and functions. Participants explore the implications of logarithms without specified bases and how that affects the proof process.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants attempt to manipulate the equation using logarithmic properties and question the implications of using logarithms without specified bases. Some express confusion over the meaning of 'log(r)' and its conventions, while others suggest taking logarithms to different bases to clarify the proof.

Discussion Status

The discussion is ongoing, with participants providing insights and questioning each other's reasoning. Some guidance has been offered regarding the interpretation of logarithmic statements, but there is no explicit consensus on the proof's validity or approach.

Contextual Notes

There are mentions of potential misunderstandings regarding the use of logarithmic bases and the implications of trivial statements in proofs. Participants also note the need for clarity in defining bases when writing equations.

TheMathNoob
Messages
189
Reaction score
4

Homework Statement


Proof xlogby=ylogbx

Homework Equations


logb is a one to one function, that is, if logbx=logby
hint take the log in both sides of the equation and use the previous hint

The Attempt at a Solution


xlogby=ylogbx
logby log x = logbx logy
logby / logbx=logy/log x
logby/x=log(y/x)

the book says that log(r) without any base indicates that the statement is true for any base so we can say that log(y/x)=logby/x

so
logby/x=logby/x

if this is true then by the hint, x=y, so the original statement must be true
 
Physics news on Phys.org
TheMathNoob said:
the book says that log(r) without any base indicates that the statement is true for any base so we can say that log(y/x)=logby/x
What does that mean? 'log(r)' is not a statement - it contains no verb. When log is written without a base the usual convention is for it to mean log base e, although in older texts it is sometimes taken to mean log base 10.

The proof is short. Just apply the fact that ##a^c\equiv e^{c\log a}## to both sides and use the fact that ##\log_d f=\frac{\log f}{\log d}##. Here I use the standard convention of using ##\log## for ##\log_e##
 
andrewkirk said:
What does that mean? 'log(r)' is not a statement - it contains no verb. When log is written without a base the usual convention is for it to mean log base e, although in older texts it is sometimes taken to mean log base 10.

The proof is short. Just apply the fact that ##a^c\equiv e^{c\log a}## to both sides and use the fact that ##\log_d f=\frac{\log f}{\log d}##. Here I use the standard convention of using ##\log## for ##\log_e##
look this is exactly what the book says , "When log(x) is used without any base being mentioned, it means that the statement is true for any base", I think that mine would make sense if apply log base b in both sides of the equation and then I go backwards.
 
TheMathNoob said:
logby/x=logby/x
That is a trivial statement because both sides are the same. You reduced the equation you have to show to something trivially true: done.
It is much easier to read the proof if you directly take the logarithm to base b.

TheMathNoob said:
if this is true then by the hint, x=y, so the original statement must be true
Do you really mean x=y? That doesn't have to be true.
 
MathNoob said:
look this is exactly what the book says , "When log(x) is used without any base being mentioned, it means that the statement is true for any base",
That may work alright for some high-level statements, such as 'log z(u) is a linear function of u', but it's hard to think of any equations where it would work. It certainly doesn't work in this instance.

Ah, now I've worked out what the book means. The author is saying that she will only use the word 'log' without specifying a base when the statement she is making is true in all bases. That is guidance as to what she may do, not as to what you may do. When writing equations, the base needs to either be stated, or unambiguously implied (as per the e convention). The author's statement is a guide to interpreting her text, not a technique you may use in writing proofs.
 
A way to fix that: take the logarithm to base a, where a is an arbitrary positive real number.
On the other hand, and as I said before, if we want to choose a=b later, we can use log_b the whole time.
 
mfb said:
That is a trivial statement because both sides are the same. You reduced the equation you have to show to something trivially true: done.
It is much easier to read the proof if you directly take the logarithm to base b.

Do you really mean x=y? That doesn't have to be true.
so mine is right
mfb said:
A way to fix that: take the logarithm to base a, where a is an arbitrary positive real number.
On the other hand, and as I said before, if we want to choose a=b later, we can use log_b the whole time.
thank you so much, yes , I applied log base b at the beginning and came up with the trivial statement.
 
andrewkirk said:
That may work alright for some high-level statements, such as 'log z(u) is a linear function of u', but it's hard to think of any equations where it would work. It certainly doesn't work in this instance.

Ah, now I've worked out what the book means. The author is saying that she will only use the word 'log' without specifying a base when the statement she is making is true in all bases. That is guidance as to what she may do, not as to what you may do. When writing equations, the base needs to either be stated, or unambiguously implied (as per the e convention). The author's statement is a guide to interpreting her text, not a technique you may use in writing proofs.
anyways, it is wrong. I made a stupid mistake of log properties xd.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
4
Views
3K
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K