Parametric equations for football trajectory at 36 degrees

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Homework Statement



At time t, a projectile launched with angle of elevation a and initial velocity Vo has position x(t)=(Vocosa)t and y(t)=(Vosina)t-0.5gt^2, where g is the accerleatio due to gravity.



The Attempt at a Solution



(a) A football player kicks a bal at an angle of 36degrees above the ground with an initial velocity of 60 feet per second. Write the parametric eqaions for the position of the gootbal at time t seconds. g=32 ft/sec^2.

=> Solution: x(t)=(60cos36)t
y(t)=(60sin35)-16t

(b) Graph the path that the football follows.
=> I did come up with the equations but I have no idea how to draw a graph out of them.
HELP!
 
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x=(60cos36)t
then shouldn't t=x/(60cos36)

sub that into your equation with y