Solution: Normal Force for Plane Taking Off at 45 Degrees

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SUMMARY

An airplane taking off at an acceleration of 3.5 m/s² at a 45-degree angle requires calculating the normal force acting on the pilot, who has a mass of 50 kg. The gravitational force (Fg) acting on the pilot is 490 N. Given the angle, the normal force components are equal, resulting in a total normal force (FN) of 692.96 N directed at 45 degrees west of north. The acceleration of the plane does influence the normal force experienced by the pilot.

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Homework Statement


An airplane is taking off at an acceleration of 3.5 m/s2at an angle of 45 degrees relative to the horizontal. Find the Normal force and its direction that is acting on the pilot if the mass of the pilot is 50 kg.



Homework Equations





The Attempt at a Solution



Fg = FNy
(50)(9.8) = FNy
FNy = 490 N

Since there is an angle of 45 degrees, FNy = FNx, So FNx = 490 N

FNx2 + FNy2 = FN2

FN = 692.96 N at an angle of 45 degrees west of north.
 
Last edited:
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Do you think the acceleration of the plane will affect the normal force?

(And be careful when quoting your angle at the end!)
 
The pilot gets 2 forces from accelerations: gravity and takeoff. Also, this won't be a compass direction problem, it will be a left/right up/down problem.
 

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