View Full Version : How to prove the half number factorial formula?
laker88116
Dec1-05, 04:28 PM
Any ideas on how to prove this?
(n+\tfrac{1}{2})! = \sqrt{\pi} \prod_{k=0}^{n}\frac{2k+1}{2}
You've presumably met the Gamma function. Have a look through identites involving Gamma that you know, you should find something useful.
HallsofIvy
Dec1-05, 06:54 PM
How do you define (n+ 1/2)!???
(Schmo already told you that- my point is you should think about it!)
laker88116
Dec1-05, 08:41 PM
Problem is, I don't know what Gamma is other than a greek letter. I can use the formula, that's not the problem. I just was curious if there was a way to prove it. I was messing with my calculator and I noticed that half numbers have factorials and other decimals don't. So, I looked this up. I am not sure what level math it is. I am through Calc 2. If you could let me know what these identies are, I would appreciate it.
CRGreathouse
Dec1-05, 09:01 PM
Problem is, I don't know what Gamma is other than a greek letter. I can use the formula, that's not the problem. I just was curious if there was a way to prove it. I was messing with my calculator and I noticed that half numbers have factorials and other decimals don't. So, I looked this up. I am not sure what level math it is. I am through Calc 2. If you could let me know what these identies are, I would appreciate it.
\Gamma(x)\Gamma(1-x)=\frac{\pi}{\sin(\pi x)}
For nonnegative integers, \Gamma(x+1)=x!. It is sensible to expand the notation x! to all real numbers other than the nonpositive integers.
laker88116
Dec1-05, 09:08 PM
I'm not understanding that. What does it have to do with my equation I listed.
Okie, you know that (and how) factorial n! is defined on the integers. We define Gamma as:
\Gamma(x)=\int_{0}^{\infty}t^{x-1}e^{-t}dt
for all x>0 real numbers. Then you, having completed calc 2, can prove the following:
-the integral in the definition of Gamma does indeed converge when x>0
-for all x>0, \Gamma(x+1)=x\Gamma(x), the "Functional equation" of gamma
-if n is a non-negative integer, then n!=\Gamma(n+1), which justifies calling Gamma an extension of factorial.
Some calculators will use Gamma to make sense of arguments of x! that are not non-negative integers, and are essentially defining x!=\Gamma(x+1) when x is a real number greater than -1. I find it odd that yours does half integral values but not other decimals. I believe you, it just seems like an odd thing to do.
To prove your formula, you can use the identity involving sine CRGreathouse supplied to find \Gamma(1/2), then use the functional equation above to find Gamma at 3/2, 5/2, ... n/2 (using induction) then translate back to factorial to get the equation in your first post. Alternatively, look directly at the integral definition of \Gamma(1/2) and try to relate it back to the Gaussian probability integral.
laker88116
Dec1-05, 10:23 PM
Alright, that makes sense, thanks.
mathwonk
Dec1-05, 11:23 PM
Riemann observed in one of his early papers that this expression for factorials of non integers allows differentiation to non integral orders, since by the cauchy integral formula differentiation to a non integral order t, simply requires one to integrate a non integral power, no problem, and determine the appropriate non integral factorial to multiply the integral by.
so you can take the 1/2 derivative of something, e.g. or even the ith, I suppose.
this is a little industry today.
rman144
Aug13-08, 01:43 AM
I have a somewhat related question. Is there/ does anyone know of a similar equation to the first one shown on this page for quarter integers. Basically:
(n+1/4)!
And particularly one that does not involve the gamma function.
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