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can anyone explain how to do this proof?
Given: angle ABC is congruent to angle ABD, angle ACB is congruent to angle ADB
Prove: triangle ACB is congruent to triangle ADB.
thank you!
Do you have any theorems that you can use? Like the angle-side-angle theorem?
If you have that, and you can show that BAD and BAC are the same, then you're done.
yeah...i think i could use the ASA theorem...but i dunno how to explain it and when to use it.
You know that the sum of the interior angles of a triangle is always the same, right?
So you know that:
ABC + BCA + CAB = ABD + BDA + DAC
from the problem you have:
ABC=ABD
and
BCA=BDA
so if you make the substitutions you get
ABC+BCA+CAB=ABC+BCA+DAC
ABD+BCA can be cancellet from both sides, so you get
CAB=DAC
oh...i get it now! thanx!
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