View Full Version : Calc help!
tandoorichicken
Dec11-03, 08:00 PM
Ummmm.....
If h(x)= -h(-x) for all x, what is \int_{-a}^{a} h(x) \,dx
????
StephenPrivitera
Dec11-03, 08:15 PM
Draw a picture! It should be clear. What does h(x)=-h(-x) mean? What does a definite integral represent if h(x) is positive?
Think of h(x)=x3 for instance. This should make the answer clear.
It means it's flipped around the origin.
That question must want a really really generic answer because if it wanted anything specific, you could just make up an answer very easily.
StephenPrivitera
Dec12-03, 12:55 AM
Originally posted by ShawnD
That question must want a really really generic answer because if it wanted anything specific, you could just make up an answer very easily.
There's only one possible answer.
0
\int_{-a}^{a} h(x) \,dx =\int_{-a}^{0} h(x)dx + \int_{0}^{a}h(x)dx=\int_{-a}^{0}-h(-x)dx+\int_{0}^{a}h(x)dx
Suppose H(x)+C=\int h(x) \,dx
\int_{-a}^{0}-h(-x)dx+\int_{0}^{a}h(x)dx=\int_{0}^{-a}h(-x)dx+\int_{0}^{a}h(x)dx
Using u=-x, du=-dx
\int_{0}^{-a}h(-x)dx+\int_{0}^{a}h(x)dx=-\int_{0}^{a}h(u)du+\int_{0}^{a}h(x)dx
=-H(a)+H(0)+H(a)-H(0)=0
What you just wrote is true with EVERY function that has a real domain and is in the form a^b where b is an integer and NOT a variable. Lets look at the integration of X^2 between -1 and 1 then between -1 and 0 then 0 and 1.
from -1 to 1 = 2/3
from -1 to 0 and 0 to 1 = 1/3 + 1/3 = 2/3
Lets try another equation, this time something like (5 - 2x)^4 - 10x +7 between -10 and 10
from -10 to 10 = 1052640
from -10 to 0 and 0 to 10 = 976820 + 75820 = 1052640
That's just way too generic to be the answer he's looking for.
StephenPrivitera
Dec12-03, 01:26 AM
f(x)=x^2 does not satisfy the hypothesis f(x)=-f(-x)
f(x)=x^2 is EVEN
f(x)=-f(-x) means f is ODD
himanshu121
Dec12-03, 02:01 AM
Definte Integrals includes + as well as - signs
area below the x-axis is -
area above the x-axis is +
Now the function is odd therefore it issymmetric with I & III quadrant
Hence if one area is positve the other will be negative.
result the integral will be zero under the limits i repeat under the limits -a to +a
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