View Full Version : Calculus
roy5995
Dec16-03, 05:38 PM
What are the first and second derivatives of the function
f(x)=(3-x)/(2x+5)
How do i find them, do i use the quotient rule or do i change it to
f(x)=(3-x)*(2x+5)^-1 and use the product rule?
Personally I like the product rule better, but you get the same answer either way, so use whichever one you prefer.
roy5995
Dec16-03, 05:50 PM
I think i got it
f'(x)= -11(2x+5)^-2
f''(x)= 44(2x+5)^-3
but does anyone know of a web site where i can type in the function and it will show me all the max, mins, asymptotes, holes, cusps ...
You made a mistake when you combined your terms in the first deriv., & therefore the 2nd is wrong too.
himanshu121
Dec16-03, 11:48 PM
You haven't applied the Product Rule properly
http://www.math.temple.edu/~cow/
How are roy's answers incorrect?
f'(x)= -11(2x+5)^-2
f''(x)= 44(2x+5)^-3
-11 times the quantity (2x+5) to the power of -2 is the correct answer as seen HERE: (http://home.twmi.rr.com/faust9/calc%20problem.jpg)
roy's answer could be written:
f'(x)= -11/(2x+5)^2
f''(x)= 44/(2x+5)^3
and it would be equivalent to what he has above.
himanshu121
Dec17-03, 01:54 AM
Sorry those are not incorrect
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