PDA

View Full Version : magnitude and direction


physics_ash82
Mar1-06, 02:00 PM
Hi I'm stuck on this problem I its got to be something simple.Here goes....

A proton moves perpendicularly to a uniform magnetic field B at 1.0x10^7 m/s and exhibits an acceleration of 2.0x10^13m/s^2 in the + x-direction when its velocity is in the + z-direction. Determine the magnitude and direction of the field.

I have been trying to use B= F/qvsin(theta)
theta = 1
q = 1.6x10^-19


and then I have the problem :blushing: So any other help would be useful thankx

ash

DaMastaofFisix
Mar1-06, 10:14 PM
Think about the use of the right hand rule and think it through. If our not to secure with that and you aregood at vectors math, try working out the cross products and such. If your still stuck let us know what's up.

P.S; the magnitude is given.

thegreenone63
Mar1-06, 10:25 PM
The right hand rule is a great tool if used. Try to use it to work out the problem, it makes things so much simpler.

physics_ash82
Mar2-06, 01:24 PM
I figured it out I was using the right formula and had forgotten that the mass of the proton is 1.67x10^-27 and I was using the charge which was 1.6 x10^-19.. but thank you for the idea on right hand rule that helped with the 2nd part.

ash:smile: