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Amith2006
Mar11-06, 01:29 PM
Sir,
Please help me in solving this problem.
# A steel ring of radius r and cross sectional area A is fitted on to a wooden disc of radius R(R>r). If the Young’s modulus be Y, then what is the force with which the steel ring expands?
I just don’t have any idea on how to go about this problem.

Gokul43201
Mar11-06, 01:39 PM
Is that the exact wording of the question ?

It is extremely ambiguous, and as such, is bordering on nonsensical.

clive
Mar11-06, 02:21 PM
For a very small portion of the ring (dl=Rd \theta) you have the static equilibrium condition:
2 T sin(\frac{d \theta}{2})=N
where N is the force between the ring and the cylinder. Now you use
sin (\frac{d \theta}{2}) ~= \frac{d \theta}{2}
and T from the Young law for the small element dl (when it expands between dl_0=r d \theta and dl=R d\theta) and so on....