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sauri
Mar17-06, 06:01 PM
A golf ball is putted too fast and rolls past the hole in a straight line, coming at closest approach to a distance d from the hole. Ignore friction and assume that golf ball moves at constant velocity.
What is the angular momentum of the golf ball about the hole?
Is the angular momentum constant about this point?

I belive that the angular momentum is constant but its direction changes due to an external torque. Yet the equation to use is beyond me could it be d(theta)=dL/L?

Da-Force
Mar17-06, 06:10 PM
Actually... When we say a golf ball has a constant velocity, all the forces must add up to be zero.

Start with that by drawing components then doing a sum in the X and Y directions.

Doc Al
Mar17-06, 06:57 PM
What is the angular momentum of the golf ball about the hole?

Consider the definition of the angular momentum of a particle:
\vec{L} = \vec{r} \times \vec{p}