Partial integration

[kallazans]

if you are not lazy, you will answer what is the general antiderivative of (2x^3+3x^2+x-1)/((x+1)*((x^2+2x+2)^2))

[suyver]

Originally posted by kallazans
S((2x^3+3x^2+x-1)/(x+1)(x^2+2x+2))dx!
are you like this?

I don't understand your question, and your equation is unclear. Do you mean

\int ((2x^3+3x^2+x-1)/(x+1)(x^2+2x+2)) {\rm d}x =

\int\frac{2x^3+3x^2+x-1}{x+1}(x^2+2x+2){\rm d}x =

-x+\frac{x^2}{2}+2x^3+\frac{5x^4}{4}+\frac{2x^5}{5}-\log(1+x)

or do you mean

\int ((2x^3+3x^2+x-1)/\left((x+1)(x^2+2x+2))\right) {\rm d}x =

\int\frac{2x^3+3x^2+x-1}{(x+1)(x^2+2x+2)}{\rm d}x =

2x-\arctan(1+x)-\log(1+x)-\log(2+(2+x)x)