View Full Version : pesky remainder problem
tandoorichicken
Dec23-03, 11:52 AM
If p(x) = (x+2)(x+k) and if the remainder is 12 when p(x) is divided by x-1, then what is the value of k?
fffbone
Dec23-03, 12:48 PM
I'm not sure if it is the right answer, but I think it is 3.
After using long division, we get the remainder 3k+3, which equals 12, meaning k=3.
No Name Required
Dec23-03, 01:23 PM
Yes that is rite, found by long division or by saying that when x=1, expression =12 (remainder theorem or something like that)
(1+2)(1+k)=12
k=3
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