What is the Value of k if the Remainder of p(x) Divided by x-1 is 12?

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The polynomial p(x) = (x+2)(x+k) yields a remainder of 12 when divided by x-1. By applying the Remainder Theorem, substituting x=1 into the polynomial results in the equation (1+2)(1+k) = 12. Solving this equation reveals that the value of k is definitively 3.

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If p(x) = (x+2)(x+k) and if the remainder is 12 when p(x) is divided by x-1, then what is the value of k?
 
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I'm not sure if it is the right answer, but I think it is 3.

After using long division, we get the remainder 3k+3, which equals 12, meaning k=3.
 
Yes that is rite, found by long division or by saying that when x=1, expression =12 (remainder theorem or something like that)

(1+2)(1+k)=12

k=3
 

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