that one i can't get it

[moham_87]

hi, i'm sorry i'm asking alot, but that time i need help

here the question says:
* Verify the inequality without evaluating the definite integrals:

(integration [x^2] from 0 to 1) >= (integration [x^3] from 0 to 1)

i can't solve that question without evaluating the integral
so how can i start it???

thank u alot ...and any efforts will be appreciated

N.B. if anyone please could inform me how to write mathematical equations in a better form.

[Njorl]

I'll give you a hint. Can you show that for all points on the interval x^2>=x^3?

Njorl

[PrudensOptimus]

Originally posted by moham_87
hi, i'm sorry i'm asking alot, but that time i need help

here the question says:
* Verify the inequality without evaluating the definite integrals:

(integration [x^2] from 0 to 1) >= (integration [x^3] from 0 to 1)

i can't solve that question without evaluating the integral
so how can i start it???

thank u alot ...and any efforts will be appreciated

N.B. if anyone please could inform me how to write mathematical equations in a better form.


take the dy/dx of both sides.

[Hurkyl]

Here's how you would write the equation:


\int_0^1 x^2 \, dx \geq \int_0^1 x^3 \, dx


(click the image to see the source code)

[himanshu121]

You draw the graphs for x^2 & x^3
In the interval [0,1]
The area under the graph for x^2 is greater than x^3


\Rightarrow\int_0^1 x^2 \, dx \geq \int_0^1 x^3 \, dx