New method finding moment of inertia of a soild sphere

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SUMMARY

The moment of inertia of a solid sphere is definitively calculated as I = 2/5 mR². This value can be derived using various methods, including the summation of point masses I = ∑ mᵢrᵢ² and the integral approach I = ∫ r² dm, which is more precise. Additionally, the relationship between rotational inertia and kinetic energy is established through the equation K = 1/2 I ω², where ω represents angular speed. The discussion highlights the potential for multiple methods to derive this result, with one participant referencing a total of 18 different approaches.

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  • Basic concepts of kinetic energy in physics
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  • Research advanced calculus techniques for deriving moments of inertia
  • Explore the application of the parallel axis theorem in rotational inertia
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Q. Show the moment of inertia of sphere is 2/5mR^2
using many different methods.

My professor said he knew 18 different method.
Do you have a new idea?
Tell me anything you know. I hope one of your methods will be the 19th method.
 
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The inertia for a point mass is [tex]I = mr^{2}[/tex]. If you have a sphere you can treat it as a large number of point masses and add them together as in [tex]I = \sum m_{i}r_{i}^{2}[/tex]. It is probably better to solve this using calculus though. For rotational inertia the equation [tex]I = \sum m_{i}r_{i}^{2}[/tex] is an approximation of [tex]I = \int r^{2} dm[/tex].

Rotational inertia is also related to kinetic energy. Kinetic energy can be expresses as [tex]K = \frac{1}{2} I \omega^{2}[/tex] where [tex]\omega[/tex] is the angular speed.

I've never heard anyone say that there 18 ways to solve this problem, but I suppose it might depend on what other information you might be given.

hope that helps

-dim
 
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