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How do I write the negation of:
For all x > 0, x^2 + y^2 > 0 for all y.
I thought it might be this:
There exists x < or = to 0 such that x^2 + y^2 < or = to 0 for one y value.
Thanks.
Originally posted by Caldus
How do I write the negation of:
For all x > 0, x^2 + y^2 > 0 for all y.
I thought it might be this:
There exists x < or = to 0 such that x^2 + y^2 < or = to 0 for one y value.
Thanks.
I think that was close but not exact, it is:
There exist one x > 0 such that x^2+y^2 < or = 0 for one y.
The thing is that there is no statement about x < 0. So that there must be no statement for x <0 in the negation.
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Maybe an better formulation (and equivalent) of the problem is:
How do I write the negation of:
For all x>0 and for all y, x^2 + y^2 > 0.
Result:
There exist one x>0 and there one y such that x^2 + y^2 <= 0.
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I hope it did help...
Whoops, I did that wrong. The actual statements are (for the problem, not the solution):
For every x >0, x^2 + y^2 > 0 for all y.
Close enough I guess?
\forall x>0 \exists y>0 \] s.t. \[ x^2+y^2 \leq 0
Originally posted by NateTG
\forall x>0 \exists y>0 \] s.t. \[ x^2+y^2 \leq 0
What is that in English? Thanks.
HallsofIvy
Jan21-04, 10:44 AM
What is that in English? Thanks.
"For all x greater than 0, there exist a y> 0
such that x^2+ y^2\leq0"
(It is, by the way, false.)
Right, but it is the negation of the statement he made.
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