View Full Version : working backwards
programmer
Aug31-06, 10:13 AM
I've taken Calculus 1, but it was a few years ago, so bear with me. I understand how to use derivitaves to find critical numbers, relative max's and min's, points of inflections, incresing, decreasing. all that good stuff.
my question is, if I have two points I want a x^3 line pass through, how can i accomplish this?
VietDao29
Aug31-06, 10:21 AM
my question is, if I have two points I want a x^3 line pass through, how can i accomplish this?
y = x3 is a curve, not a line.
I don't really get what you mean. y = x3 is a specific curve, i.e you cannot change the set of points that it passes through.
If you want to get 2 points on the curve, just choose 2 arbitrary x1, and x2 values, then from there find the corresponding y1, and y2. And you'll have 2 points that the curve passes through.
programmer
Aug31-06, 10:28 AM
no, i want to MODIFY a x^3 equation to MAKE it pass through the points i already have set.
programmer
Aug31-06, 10:32 AM
the first point is 0,0, and the 2nd point could be anything, how to i alter the curve to make it pass through my 2nd point?
You're trying to curve-fit a cubic to some known data set.
Look up cubic spline interpolation. Numerical Recipes in C has a section on it, with the algorithm coded in C.
http://www.library.cornell.edu/nr/cbookcpdf.html
If you only have two points, one of which is (0, 0) and the other is (x0, y0), just solve this equation for a:
a x_0^3 = y_0
- Warren
HallsofIvy
Sep3-06, 05:51 AM
There are many different ways to do this. For example, as chroot said, if you want a formula of the form y= ax3, which necessarily passes through (0,0) for all a, just select a so that y0= ax3: That is y= \left(\frac{y_0}{x_0^3}\right)x^3 passes through (0,0) and (x0,y0).
Or, you could alter y= x3 to look like y= x3+ ax. In order to have y= y0 when x= x0 we must have y_0= x_0^3+ ax_0 or, solving for a, a= \frac{y_0- x_0^3}{x_0}. That is, the graph of y= x^3+ \frac{y_0- x_0^3}{x_0}x passes through (0,0) and (x0,y0). There are many other possiblities. The choice is essentially arbitrary unless you have other conditions to fulfill.
programmer
Sep7-06, 08:20 PM
well....i guess I've forgotten a lot of calculus...what does the I in those equations stand for? Integral?
HallsofIvy
Sep8-06, 05:32 AM
well....i guess I've forgotten a lot of calculus...what does the I in those equations stand for? Integral?
?? What I are you talking about? Which response does this relate to?
programmer
Sep8-06, 01:29 PM
nevermind...the X's in those equations look like I's...
that's retarded
nevermind...the X's in those equations look like I's...
that's retarded
Mm... that's how all x's are typeset in every math book I've ever seen.
- Warren
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