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mcintyre_ie
Jan25-04, 09:24 AM
Hey,
I'd appreciate any help you can give with this question – I've already tried it but I don’t think my solution is correct. Any advice on where (or if) I went wrong?
Thanks in advance

The Question:
Solve the differential equation:

2x(1+y) dx/dy = 8 + x^2
if x = 2 when y = 3

My solution:
Solution (http://community.webshots.com/photo/103485906/113638426ZpNzPs)
(Revised link)

himanshu121
Jan25-04, 09:29 AM
The link doesnt allow me to access Still
u have
2x(1+y)dx/dy=8+x^2
It requires rearrangement

so u have
\frac{2x}{8+x^2}dx=\frac{dy}{1+y}
Hope u will take it from here[:))]

mcintyre_ie
Jan25-04, 02:48 PM
Sorry about the bad link, i think ive fixed it now though.

himanshu121
Jan25-04, 03:29 PM
Yup it is correct