acid/base balancing question (given products)

[lorka150]

I have a question and I dont even know where to begin. Perhaps someone can guide me.

For these products:
RbBr(aq)
NaCH3CO2(aq)
Fe(ClO4)3 (aq)

I need to write the balanced equation and the net ionic euqation for each of them. nd indicate their states (aq, s, l)... (s) is the precipitation one.

Please?!!!

[cheechnchong]

well, you are given products sooo...

you know a reaction consists of reactants and products right?

reactants ----> products

for example:
2Rb(s) + Br(2) (aq) ---- 2RbBr (aq)

(i hope you know what a diatomic molecule is? H, O, F, Br, I, Cl ... these elements cannot be free as a single atom)

but from that written equation we can breakdown the ionic equation...

2Rb+(s) + 2Br-(aq) ------ 2Rb+(aq) + 2Br-(aq) (RbBr breaks down because it is soluble...search
Solubility on wikipedia.org if you're not familiar with the rules)

Thus the net ionic equation (where spectator ions cancel out):

2Rb+(s) ----- 2Rb+(aq) (2Br cancel because they're spectator ions) (Rb dont cancel b/c they're in different states)

^^^Here's your answer for part 1...You only need to see it once for these kinds of problems, but if you need more help PM or post here

[lorka150]

Example: How can Lao(SOo), be produced? Ans. From the reaction of La(OH), (base) with HrSOo
(acid)
Molecularz 2La(OH), (s) + 3 HrSO4 (aq) -+ Lq(SOa), (aq) + 6 HrO (l)
Net ionic: La(OH), (s) + 3 H. (aq) -+ Lf* (aq) + 3 H2O (l) (Note lowest whole #'s in equation)

I was given that example... So I actually have to use the acid and base in the reaction. That is why I am confused.

[cheechnchong]

^^^hey by the way, i just remembered an arguement a few days ago about somethin on the question i helpled u with. I'm not sure the 2Br cancels out...you might wanna check for that!

[cheechnchong]

Example: How can Lao(SOo), be produced? Ans. From the reaction of La(OH), (base) with HrSOo
(acid)
Molecularz 2La(OH), (s) + 3 HrSO4 (aq) -+ Lq(SOa), (aq) + 6 HrO (l)
Net ionic: La(OH), (s) + 3 H. (aq) -+ Lf* (aq) + 3 H2O (l) (Note lowest whole #'s in equation)

I was given that example... So I actually have to use the acid and base in the reaction. That is why I am confused.

hmmmm that's weird...it might have been a mistake by the teacher/prof. I can see that H2SO4 breaks down (because it is a strong acid) and the LaOH is insoluble because of the solubility rule. Other than that i cannot understand the balancing part of this question--for some reason! i hope someone comes in here to save you