Proof Involving Binary Operators

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Discussion Overview

The discussion revolves around proving the set equality A union (B intersection C) = (A union B) intersection (A union C), which is one of DeMorgan's Laws. Participants are exploring the proof through logical reasoning and case analysis without the use of Venn diagrams.

Discussion Character

  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant proposes a proof strategy by considering cases for x belonging to A union (B intersection C).
  • Another participant corrects the initial reasoning regarding Case 2, clarifying that if x belongs to (B intersection C), then it must belong to both (A union B) and (A union C).
  • A later reply suggests that to prove the subset relationship, one must show that if x is in (A union B) intersection (A union C), then it is also in A union (B intersection C), but expresses uncertainty about how to proceed.
  • Another participant emphasizes that proving set containment often involves showing that an element in one set is also in the other by considering all cases.

Areas of Agreement / Disagreement

Participants are engaged in a collaborative proof process, but there is no consensus on the final steps or the correctness of the reasoning presented. Multiple viewpoints and approaches are being discussed.

Contextual Notes

Some participants express uncertainty about specific steps in the proof, particularly regarding the implications of membership in the sets involved. There are also references to the necessity of considering all cases in set containment arguments.

Caldus
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I am trying to prove that A union (B intersection C) = (A union B) intersection (A union C). In other words, proving one of DeMorgan's Laws. I have gotten this far, and not sure if I'm right thus far:

Let x belong to A union (B intersection C). Then x is in either A or in (B intersection C).

Case 1: x belongs to A.
In this case, x belongs to (A union B) and x belongs to (A union C).

Case 2: x belongs to (B intersection C).
In this case, x belongs to either (A union B) or (A union C).

So x belongs to ((A union B) intersection (A union C)) union ((A union B) union (A union C)).

((A union B) union (A union C)) can be rewritten as (using associative property):

(A union B union A union C), or simply (A union B union C).

What do I do now? Thank you.
 
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Case 2: x belongs to (B intersection C).
In this case, x belongs to either (A union B) or (A union C).

No, if x belongs to (B intersection C),then x belongs to both (A union B) and (A union C).
(since x belongs to (B intersection C) it is in both B and C and so in both (A union B) and (A union C) so it is in
(A union B)intersection (A union C).)
 
OK this is what I got now:

First, we must prove that A union (B intersection C) is a subset of (A union B) intersection (A union C).

So we let x belong to A union (B intersection C). Then x is in A or (B intersection C).

Case 1: x belongs to A.
In this case, x belongs to (A union B) and x belongs to (A union C).

Case 2: x belongs to (B intersection C).
In this case, x belongs to (A union B) and x belongs to (A union C).

So x belongs to ((A union B) intersection (A union C)).

Now we have to prove that (A union B) intersection (A union C) is a subset of A union (B intersection C).

So now let x belong to (A union B) intersection (A union C). Then x is in A. x is in either B or C.

Case 1: x is in B.
In this case, x belongs to (A union B).

Case 2: x is in C.
In this case, x belongs to (A union C).

Am I right so far? I don't know how to go any farther with this.

Thanks for the help so far.
 
Why not do it with Venn diagrams?
 
I have to solve it without using Venn Diagrams.
 
How can I conclude that (A union B) intersection (A union C) is a subset of A union (B intersection C)?
 
almost any question about the containment or equality of sets boils down to showing x in A implies x in D

so take something in one and show it's in the other by considering all cases if necessary. here x is in AUB and AUC, if it is in A it is certainly in AU(B int C)

if it is not in A then it must be in both B and C, ie it is in (B int C), and is then also clearly in AU(BintC)
 

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