Electric Field

[eku_girl83]

Here's the problem:
A particle with a charge of 4.4nC is in a uniform electric field E directed to the left. It is released from rest and moves to the left. After it has moved 6.00 cm, its kinetic energy is found to be 3E-6 Joules.
a) What work was done by the electric force?
.000003 J
b) What is the potential of the starting oint with respect to the endpoint?
681.818 J
I got these parts correct, but am having trouble with part c.
c) What is the magnitude of E?

Could someone give me a hint?? Thanks!!

[HallsofIvy]

You already know the work done by the electric field.

Work= force* distance so you can calculate the force that the electric field applied for that distance of 6.00 cm.

force= magnitude of electric field * charge (which is 4.4nC) so you can calculate the magnitude from the force.