PDA

View Full Version : Thermodynamics


Lee
Oct22-06, 11:58 AM
THe Question asks 'Derive the entropy of an ideal gas when its molar specific heat at constant volume is constant.'

So I've taken

\Delta S = \int_{S_0}^{S} dS = \int_{T_0}^{T} \frac{\partial_S} {\partial_V} dT + \int_{V_0}^{V} \frac{\partial_S}{\partial_V} dV

in this context what would be the next best step?

Andrew Mason
Oct22-06, 03:41 PM
THe Question asks 'Derive the entropy of an ideal gas when its molar specific heat at constant volume is constant.'

So I've taken

\Delta S = \int_{S_0}^{S} dS = \int_{T_0}^{T} \frac{\partial_S} {\partial_V} dT + \int_{V_0}^{V} \frac{\partial_S}{\partial_V} dV

in this context what would be the next best step?If the specific heat remains constant at all temperatures, then it is possible to integrate from temperature 0 to T.

Since dQ = TdS = dU + PdV = nC_vdT + PdV at constant volume nC_vdT = TdS

so:

\int_0^T dS = \int_0^T nC_v dT/T = S_T - S_0

If you let the entropy of the gas at 0 K be 0: S_0 = 0, then ST represents the entropy of the gas at temperature T.

AM