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THe Question asks 'Derive the entropy of an ideal gas when its molar specific heat at constant volume is constant.'
So I've taken
\Delta S = \int_{S_0}^{S} dS = \int_{T_0}^{T} \frac{\partial_S} {\partial_V} dT + \int_{V_0}^{V} \frac{\partial_S}{\partial_V} dV
in this context what would be the next best step?
Andrew Mason
Oct22-06, 03:41 PM
THe Question asks 'Derive the entropy of an ideal gas when its molar specific heat at constant volume is constant.'
So I've taken
\Delta S = \int_{S_0}^{S} dS = \int_{T_0}^{T} \frac{\partial_S} {\partial_V} dT + \int_{V_0}^{V} \frac{\partial_S}{\partial_V} dV
in this context what would be the next best step?If the specific heat remains constant at all temperatures, then it is possible to integrate from temperature 0 to T.
Since dQ = TdS = dU + PdV = nC_vdT + PdV at constant volume nC_vdT = TdS
so:
\int_0^T dS = \int_0^T nC_v dT/T = S_T - S_0
If you let the entropy of the gas at 0 K be 0: S_0 = 0, then ST represents the entropy of the gas at temperature T.
AM
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