Urgent!!

[BLUE_CHIP]

What does the A stand for in the equation:

y=A\sin{(kx-t\omega)}



CHEERS :)

[chroot]

Amplitude.

- Warren

[himanshu121]

max value of the displacement from the mean position

[BLUE_CHIP]

thanks :)

but could you answer this

whats the relationship between k and the wavelength of the wave

[himanshu121]

k=\frac{2\pi}{\lambda}

[chroot]

Think about it. If x is the displacement along a taught string, the wavelength of a wave on that string is the distance between successive crests or troughs.

All sine waves repeat every 2 pi radians.

When x = \lambda, you want the argument to be 2 \pi.

Try rewriting the first term (the term with the x) as:

\frac{2 \pi x}{\lambda}

You'll see that when x = \lambda, the entire expression is 2 \pi -- exactly one period. This is the right expression.

Therefore, if you want to simplify that expression by bringing in a new symbol k, k must be

k = \frac{2 \pi}{\lambda}

- Warren

[BLUE_CHIP]

Score! thanks Boudoir

[BLUE_CHIP]

Bummer hit a brick wall again. check this out:

for the equation y=A\sin{(kx-t\omega)} find a relationship between \omega and the time period T of the wave.

when t=T y=0 and x=0

therefore:

A\sin{(-T\omega)}=0

but then what?

[chroot]

Don't you have a textbook?

\omega = 2 \pi f

T = \frac{1}{f}

T = \frac{2 \pi}{\omega}

- Warren

[GRQC]

Originally posted by chroot
Don't you have a textbook?


- Warren

I think you're doing his homework for him.

[himanshu121]

I dont find it as Homework.

Anyway He is reaching the conclusions and thats the bottom line

[BLUE_CHIP]

Thanks [:)] saved my life.