View Full Version : rotatioanl dynamics
The engine of an aircraft propeller delivers an amount of power 171. hp to the propeller at a rotational velocity of 2310 rev/min. I found the torque produced to be 527.612 N*m
How can i find the work done by the engine in one rev of the propeller?
Power is the rate at which work is done.
171 hp = 746 W = 746 J/s
You have how many revs / s ?
(J/s)/(r/s) = J/r
use this equation to find the work done: W = τθ (it's the rotational analog to W = Fd; realize that it's still a dot product, but we've simplified already)
Touche, gnome.
ACLerok: you should get the same answer either way.
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