PDA

View Full Version : Proving differentiability of function on a Lie group.


Daverz
Nov22-06, 01:51 PM
On page 116 of Choquet-Bruhat, Analysis, Manifolds, and Physics, Lie groups are defined, and the first exercise after that asks you to prove that
for a Lie group G


f:G \rightarrow G; x \mapsto x^{-1}


is differentiable. I know from the previous definitions that a function f on a manifold is differentiable at x if


\psi \circ f \circ \phi^{-1}


is differentiable, where (U, \phi) and (W, \psi) are charts for neighborhoods of x and y=f(x)=x^{-1}. It's probably an indication of how weak my analysis is, but I don't see how to proceed from there. Can anyone point me in the right direction?

Los Bobos
Nov22-06, 03:23 PM
In the books which I have used your exercise is the definition of the Lie group :smile: !?!.

Daverz
Nov22-06, 04:05 PM
Ah, OK, I see it now, you just prove it from the definition of a Lie group, which is that the map
from G \times G \rightarrow G; (x, y) \mapsto x y^{-1} is differentiable. Just let x = e, the identity element. I was making it way too difficult. BTW, does anyone know how to keep inline Latex from showing up above the line like that.

dextercioby
Nov23-06, 01:43 AM
Just use [ itex ] [ /itex ].

Daniel.