Solving Equations: Help for Math-Rusty Students

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  • Thread starter Thread starter xyxaprilxyx
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SUMMARY

The discussion focuses on solving the equation (30m/s - 10m/s)/2.0s = 10m/s², aimed at assisting individuals who feel rusty in mathematics. The step-by-step breakdown illustrates how to simplify the equation, resulting in an acceleration of 10m/s². Key steps include subtracting the velocities, dividing by time, and understanding the units of measurement. The final answer confirms the proper application of physics principles related to acceleration.

PREREQUISITES
  • Basic understanding of algebraic operations
  • Familiarity with units of measurement in physics (meters, seconds)
  • Knowledge of acceleration concepts in physics
  • Ability to manipulate fractions and units
NEXT STEPS
  • Review algebraic manipulation techniques for solving equations
  • Study the concept of acceleration and its units in physics
  • Practice solving similar equations involving velocity and time
  • Learn about dimensional analysis to ensure unit consistency
USEFUL FOR

This discussion is beneficial for students returning to mathematics after a break, educators seeking to explain physics concepts, and anyone looking to reinforce their understanding of basic algebra and acceleration calculations.

xyxaprilxyx
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I haven't had any math in like 4 years and I'm very rusty. Could someone please show me a "step by step" how to solve an equation like this...

(30m/s - 10m/s)/2.0s = 10m/s^2

I forgot how to get to the answer.This example came from my book. Can someone please explain how the answer became 10m/s^2 ?



I got lost with the metere/second square

Please help

Thanks in advance.
 
Last edited:
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[tex]\frac{(30m/s - 10m/s)}{2.0s} =[/tex]

[tex]\frac{(20 m/s) }{ 2s} =[/tex]

[tex]\frac{20}{2}\frac{m/s}{s} =[/tex]

[tex]10 \frac{m}{s}\frac{1}{s}=[/tex]

[tex]10\frac{m}{s^2}[/tex]


Remember: [tex]\frac{a}{b}/c=\frac{a}{b*c}[/tex]
 
THANKS...

that helped a lot


~April
 

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