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giant016
Dec17-06, 06:22 PM
1. The problem statement, all variables and given/known data

http://i106.photobucket.com/albums/m255/giant016/physics.jpg

2. Relevant equations
Net force of the Y vector: -F1 + F2 - weight = 0


3. The attempt at a solution

I tried to solve the equation thinking that m could = torque (torque=force X length of lever arm) but I couldn't figure out how to fit in that .025m spot in between the joint and the muscle. Not sure if the equation provided will really help. Any help is appreciated!

ShawnD
Dec17-06, 06:30 PM
The question is tricky because the M force is drawn in the wrong direction. The M force is the blue arrow up, not a black arrow going right. Put an equation equal to 0 where clockwise moments are positive and counterclockwise are negative
0 = (0.025)(M) + (0.15)(22) - (0.3)(111)
M = 1200N

That doesn't seem right. That's equivalent to 122kg, resting on 1 muscle.

giant016
Dec17-06, 06:38 PM
The question is tricky because the M force is drawn in the wrong direction. The M force is the blue arrow up, not a black arrow going right. Put an equation equal to 0 where clockwise moments are positive and counterclockwise are negative
0 = (0.025)(M) + (0.15)(22) - (0.3)(111)
M = 1200N

That doesn't seem right. That's equivalent to 122kg, resting on 1 muscle.

We have an answer sheet (it's a multiple choice question) and one of the answers is 1.2X10^3, and your equation makes sense, so...Thanks! I'm on some other forums (mostly car junk) and I've never gotten an answer that quick!