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mark9696
Feb21-04, 05:25 PM
A particle moves on a circular orbit in a central force field. The origin of the force lies on the circle.

Find the polar equation of the orbit.


I am confused as to how to set up this question.

Dr Transport
Feb21-04, 09:11 PM
Start with the equation for the invers radius of the orbit with respect to angle

{d^2u}\over {d/ \theta^2} + u =

Dr Transport
Feb21-04, 09:19 PM
Can't work it right now, back later....... anyway it is r^-5.

mark9696
Feb22-04, 10:16 AM
I need a few more steps to be explained. I am sure that if you could please explain them to me that I will get it.

mark9696
Feb22-04, 10:23 AM
Also, I ahve never sen that queation before. IS it derived somewhere on the net?

Are you saying that the polar equation is r^(-5)? I need some help here desparately.

Dr Transport
Feb22-04, 05:01 PM
My typing is bad, and it was late.

Start with Goldstein 3-34a,

\frac{d^2 u}{d\theta^2} + u = -\frac{m}{l^2u^2}f(1/u)

Dr Transport
Feb22-04, 05:06 PM
My typing is bad, and it was late.

Start with Goldstein 3-34a,

\frac{d^2 u}{d\theta^2} + u = -\frac{m}{l^2u^2}f(1/u)

set 1/u = 2acos\theta and crank away. The answer should pop out when you eliminate the \theta .

For some reason, the \frac is not working........

Dr Transport
Feb22-04, 05:07 PM
I guess it did work in the final compile......