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stunner5000pt
Dec23-06, 02:35 PM
1. The problem statement, all variables and given/known data
Griffiths Problem 7.8
A square loop of wire (side a) lies on a table dsiantce s from a very long straight wire, which carries a current I, as shown in teh figure.

Find the flux of B through the loop

2. Relevant equations
Flux of B is given by
\Phi_{B} = \int \vec{B} \dot d\vec{a}


3. The attempt at a solution
THe area element is constant
but hte magnetic field is not
For a wire, B at a dsitance r is given by
\vec{B} = \frac{\mu_{0} I}{2\pi r} \hat{phi}

Flux is then
\Phi_{B} = \int_{s}^{s+a} \frac{\mu_{0} I}{2\pi r} a^2 ds

but hte solution says that the area element should be just a, and not a^2 .. why is that???

thanks for help!

Doc Al
Dec23-06, 02:48 PM
but hte solution says that the area element should be just a, and not a^2 .. why is that???

The element of area is "a ds", where "ds" is distance along r: you are treating the area as infinitesimal rectangular strips, parallel to the wire.

stunner5000pt
Dec23-06, 02:51 PM
The element of area is "a ds", where "ds" is distance along r: you are treating the area as infinitesimal rectangular strips, parallel to the wire.

thank you
i get it now