stunner5000pt
Dec23-06, 02:35 PM
1. The problem statement, all variables and given/known data
Griffiths Problem 7.8
A square loop of wire (side a) lies on a table dsiantce s from a very long straight wire, which carries a current I, as shown in teh figure.
Find the flux of B through the loop
2. Relevant equations
Flux of B is given by
\Phi_{B} = \int \vec{B} \dot d\vec{a}
3. The attempt at a solution
THe area element is constant
but hte magnetic field is not
For a wire, B at a dsitance r is given by
\vec{B} = \frac{\mu_{0} I}{2\pi r} \hat{phi}
Flux is then
\Phi_{B} = \int_{s}^{s+a} \frac{\mu_{0} I}{2\pi r} a^2 ds
but hte solution says that the area element should be just a, and not a^2 .. why is that???
thanks for help!
Griffiths Problem 7.8
A square loop of wire (side a) lies on a table dsiantce s from a very long straight wire, which carries a current I, as shown in teh figure.
Find the flux of B through the loop
2. Relevant equations
Flux of B is given by
\Phi_{B} = \int \vec{B} \dot d\vec{a}
3. The attempt at a solution
THe area element is constant
but hte magnetic field is not
For a wire, B at a dsitance r is given by
\vec{B} = \frac{\mu_{0} I}{2\pi r} \hat{phi}
Flux is then
\Phi_{B} = \int_{s}^{s+a} \frac{\mu_{0} I}{2\pi r} a^2 ds
but hte solution says that the area element should be just a, and not a^2 .. why is that???
thanks for help!