What Is the Correct Normalization Constant for a Particle in a Cubic Box?

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Homework Help Overview

The discussion revolves around determining the normalization constant for a particle confined in a cubic box with infinitely hard walls. The wave function is presented, and there are questions regarding the necessity of performing a triple integral for normalization.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the value of the normalization constant A, with some suggesting it should be A^2 = L/8, while others propose A^2 = 8/L^3. There are questions about the need for a triple integral and the correctness of the wave function representation.

Discussion Status

The discussion is active, with multiple interpretations of the normalization constant being explored. Some participants provide guidance on using the average value of sin^2 for integration, while others challenge the correctness of the initial assumptions and calculations.

Contextual Notes

There is uncertainty regarding the formulation of the wave function and the necessity of performing integrals for normalization. Participants are navigating through differing interpretations of the problem setup.

jairusgarcia
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Homework Statement



A particle is in a cubic box with infinitely hard walls whose edges have length L. The wave functions of the particle are given by

[tex]\psi(x)=Asin\frac{n\pi(x)}{L}Asin\frac{n\pi(y)}{L}Asin\frac{n\pi(z)}{L}[/tex]

a) Find the value of the normalization constant A.
b) Find the probability that the particle will be found in the range



Homework Equations



in a)--- both questions, do i really need to do the triple integral?

The Attempt at a Solution



is this right? [tex]A=L/8[/tex]
 
Last edited:
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It should be A^2=L/8. You can use the fact that sin^2 averages to 1/2 to do the integral quickly.
For any given range, you would have to do the integral over those limits.
 
Yes, you need to do the triple integral - but it's essentially only doing the same integral thrice. Your value for A is incorrect. Also, typically, one doesn't write the wavefunction with the normalization constant A^3 as you've written above. Are you sure that's how it is in the question given to you?
 
Meir Achuz said:
It should be A^2=L/8.
That doesn't look right. I think you may have inverted it...
 
Gokul43201 said:
I think you may have inverted it.
Sorry. It was all wrong. It should be A^2=8/L^3. I did it in my cubical head.
 

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