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Jug
Mar1-04, 12:26 AM
What is the formula in either spherical or Euclidean geometry for describing distance on the quadrant by triangulation?? Can it be done?

Guybrush Threepwood
Mar1-04, 01:32 AM
a general formula?
IMO it is dependant on the way in which you make the triangulation of the surface....

Jug
Mar1-04, 05:34 PM
Originally posted by Guybrush Threepwood
a general formula?
IMO it is dependant on the way in which you make the triangulation of the surface....

Let's say a simple Euclidean circle where any distance on the diameter defines base of the right angle triangle.

matt grime
Mar1-04, 06:09 PM
please could you rewrite the question so it makes more sense (to me): what quadrant, which triangulation, spherical geometry does not a have right angled triangle inscribed inside cicles ( a spherical circle is a weird thing to draw btw). In fact what do you mean by tringulation and what do you think it has to do with length?

Distances on ordinary, spherical and hyperbolic geometry are well defined, is that not what you want?

Jug
Mar2-04, 06:21 PM
Originally posted by matt grime
please could you rewrite the question so it makes more sense (to me): what quadrant, which triangulation, spherical geometry does not a have right angled triangle inscribed inside cicles ( a spherical circle is a weird thing to draw btw). In fact what do you mean by tringulation and what do you think it has to do with length?

Distances on ordinary, spherical and hyperbolic geometry are well defined, is that not what you want?

Matt, answered my own question (Euclidean):

A trianglature formula states that diameter of circle divided by root 2 gives length to the hypotenuse of a right angle triangle, the hypotenuse defining distance on the quadrant when multiplied by a conversiom factor of pi/4 (root 2). Thanks for the input....

Guybrush Threepwood
Mar3-04, 01:25 AM
Originally posted by Jug
A trianglature formula states that diameter of circle divided by root 2 gives length to the hypotenuse of a right angle triangle, the hypotenuse defining distance on the quadrant when multiplied by a conversiom factor of pi/4 (root 2). Thanks for the input.... [/B]

WHAT??????
this (http://mathworld.wolfram.com/Triangulation.html) is what is usually understood by triangulation.......

Jug
Mar4-04, 12:01 AM
GT,

I have no argument with the system of triangulation. Merely saying that the trianglature formula solves the given problem.