Another Friction Problem

[Peach]

1. The problem statement, all variables and given/known data
Block A in the figure View Figure weighs w_1 and block B weighs w_2. The coefficient of kinetic friction between all surfaces is u_k.

Find the magnitude of the horizontal force \vec{F} necessary to drag block B to the left at constant speed if A is held at rest (figure (b)).


2. Relevant equations
F = ma
a = 0

3. The attempt at a solution
I attempted by drawing two FBDs for A and B. I have for

B: w_2 downward, F_aonb downward, normal force upward, F to the left dragging, and fk_ground
A: w_1 downward, normal force upward, F_bona, and fk_ab

Then I solved for the normal force and I got n = (w_1+w_2)/2 and then I plugged it into the fk = ukn, but well wrong answer.

I have a few questions because I don't really understand the whole picture. There's two frictional forces acting on B right? From A and from the ground? Is this correct? Also, the normal force for both B and A...are they the same or are they different? They're different right?

[PhanthomJay]

1. The problem statement, all variables and given/known data
Block A in the figure View Figure weighs w_1 and block B weighs w_2. The coefficient of kinetic friction between all surfaces is u_k.

Find the magnitude of the horizontal force \vec{F} necessary to drag block B to the left at constant speed if A is held at rest (figure (b)).


2. Relevant equations
F = ma
a = 0

3. The attempt at a solution
I attempted by drawing two FBDs for A and B. I have for

B: w_2 downward, F_aonb downward, normal force upward, F to the left dragging, and fk_ground what about the magnitude and direction of the friction force from A on B ?
A: w_1 downward, normal force upward, F_bona, and fk_ab Specify the directions of the ones you have identified.

Then I solved for the normal force and I got n = (w_1+w_2)/2 and then I plugged it into the fk = ukn, but well wrong answer.how did you get this?

I have a few questions because I don't really understand the whole picture. There's two frictional forces acting on B right? From A and from the ground? Is this correct? correct Also, the normal force for both B and A...are they the same or are they different? They're different right?[color=red]correct[color]Draw the FBD's again and identify the forces on each block. The normal force on block A is the force upwards of B on A.

[Doc Al]

B: w_2 downward, F_aonb downward, normal force upward, F to the left dragging, and fk_ground
You left out the friction force of A on B. Note also: the force you call F_aonb downward is the normal force between A and B. A and B exert two forces on each other: a normal force and a friction force.
A: w_1 downward, normal force upward, F_bona, and fk_ab
Seems like you are counting the normal force twice: F_bona is the normal force. And you left out the tension in the rope pulling on A. (You don't need to analyze the forces on A to solve this problem, but it's good exercise.)

Then I solved for the normal force and I got n = (w_1+w_2)/2 and then I plugged it into the fk = ukn, but well wrong answer.
I assume you mean the normal force between the ground and B. How did you solve for it? (Consider vertical forces only.)

I have a few questions because I don't really understand the whole picture. There's two frictional forces acting on B right? From A and from the ground? Is this correct?
Absolutely correct.
Also, the normal force for both B and A...are they the same or are they different? They're different right?
Yes. The normal force between A & B is different from the normal force between B & ground.

[Peach]

Okay, the friction force from A to B is going in the same direction as the friction force from the ground to B right? Because friction forces are always in the opposite direction from the acceleration and perpendicular to normal forces..? If that's not wrong, then this is what I'm getting:

n_gb: n_ab + w_2

F: fk_ab + fk_gb

Is this correct? Am I going in the right direction, no pun intended?

Edit: Oh! And n_ab is w_1 right? Because the normal force on A = n_bona = w_1? That's what I'm getting from my FBD of A...

[PhanthomJay]

Okay, the friction force from A to B is going in the same direction as the friction force from the ground to B right? Because friction forces are always in the opposite direction from the acceleration and perpendicular to normal forces..? If that's not wrong, then this is what I'm getting:

n_gb: n_ab + w_2

F: fk_ab + fk_gb

Is this correct? Am I going in the right direction, no pun intended?

Edit: Oh! And n_ab is w_1 right? Because the normal force on A = n_bona = w_1? That's what I'm getting from my FBD of A...Yes, this seems correct....

[Peach]

I got the answer. Many thanks for both the help. ^^