View Full Version : Helpppp!!!!
xol0veisSuicideX
Feb23-07, 08:12 AM
What is the charge on sodium in the following reaction, formation of 2Na^x +(CO3)^2-=Na2CO3 sodium carbonate? x=Unknown?
Choices are:
+3
+2
-2
+1
-1
HELPPP MEEE!!!
Ariel
dextercioby
Feb23-07, 08:21 AM
Hmm, it looks to me that you have to solve a very simple equation. This is course you don't know the answer a priori...
What is the net charge in \mbox{Na}_{2}\mbox{CO}_{3} ?
xol0veisSuicideX
Feb23-07, 08:26 AM
I have no idea!! lol thats y im asking you guyz!!!
+Minkie+
Feb23-07, 08:41 AM
If you look closely at your equation, and the charges allready given, your answer should spring to life!
xol0veisSuicideX
Feb23-07, 09:05 AM
:confused: I still dont get it .. can you tell chemistry is not my strongest subject?:uhh:
Moonbear
Feb23-07, 09:34 AM
Please note our forum guidelines require that you show your own effort on homework questions before we can help you. Since you don't sound like you even know where to start here, why don't you tell us what you do know about balancing reactions, or what the charge on ions in these equations represents. This will help us know where to start helping you, since it seems you need a bit of a review of prior material to get caught back up to the point of being able to solve this problem.
+Minkie+
Feb23-07, 12:39 PM
2Na^x +(CO3)^2-=Na2CO3
Ok what we know from the equation;
CO3 has a charge of 2-
Two sodium ions are required
The net overall charge of Na2CO3 is 0
Things should be clearer now
Plastic Photon
Feb23-07, 12:56 PM
solve it algebraicly with what you have, Na2CO3 is neutral, 2Na is unknown and CO3 has charge -2 so...
2x - 2 = 0
+Minkie+
Feb23-07, 01:06 PM
:surprised Why don't you just give away the answer :surprised
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