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afcwestwarrior
Feb25-07, 09:52 PM
y=ex(x is suppost to be smaller and on the top right of e)/x squared

i a suppost to differentiate this, well i wrote -2ex/x cubed+ ex/ x sq.

now u probabl might be confused by the way i wrote it since i dont know how to put the right things for my problems,

well i set up the problem how do i figure out the answer,

i know the answer but how do i figure it out

ranger
Feb25-07, 10:30 PM
Is this what you are getting at y = ex/x2?

Would it help if you rewrite it as a product rule:
ex.x-2

cristo
Feb26-07, 01:32 AM
i a suppost to differentiate this, well i wrote -2ex/x cubed+ ex/ x sq.


This is correct.

Gib Z
Feb26-07, 03:40 AM
i know the answer but how do i figure it out

y=\frac{e^x}{x^2}
Let u=e^x and v=x^2.

By the quotient rule, the derivative is \frac{u'v-v'u}{v^2}

cristo
Feb26-07, 06:21 AM
i know the answer but how do i figure it out

I must've skipped over this, and so didn't notice that you wanted to know how to get the answer!!

Well, anyway, now you've got two ways; using the product rule as shown by ranger, or the quotient rule given by Gib Z.