HELP, URGENT! how do i integrate (x)^1/3

[butoyzki]

how do i solve this?
please help me integrate (X)^1/3

[okevino]

x^(-2/3) / 3

aka..
1 over 3x^(2/3)

[mezarashi]

The same way you would integrate X^1.

If I were to write X^1 as X^(3/3), would this help you see the similarity? How would you integrate X^(3/3)?

[VietDao29]

x^(-2/3) / 3

aka..
1 over 3x^(2/3)
Errr, well, it's integration, not differentiation. :rolleyes:

For all \alpha \in \mathbb{R}, not -1. We have:
\int x ^ {\alpha} dx = \frac{x ^ {\alpha + 1}}{\alpha + 1} + C

:)

[okevino]

opps..
then it's

3x^(4/3) over 4