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Blade
Mar23-04, 09:34 PM
How would I go about simplifying something like:
(n+3)!/(n+1)! ? [g)]

cookiemonster
Mar23-04, 10:22 PM
\frac{(n+3)!}{(n+1)!} = \frac{(n+3)(n+2)\cdot(n+1)!}{(n+1)!}=(n+2)(n+3) = n^2 + 5n + 6

cookiemonster