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stanners
May24-07, 11:58 PM
1. The problem statement, all variables and given/known data

int from 1 to 1/4 of [cos(pi*sqrt(t))] / sqrt(t) dt


2. Relevant equations

3. The attempt at a solution
I tried using integration by parts

used u = cos pi (sqrt(t)) and dv = sqrt(t), but got a really messy number as int of vdu

so I tried u = sqrt t, du = 1/2sqrt(t)
dv = cos pi*sqrt(t) , v = sin pi sqrt(t) * pi/2sqrt(t)


So This doesn't seem right, how would I approach this problem?

tronter
May25-07, 12:04 AM
You want \int_{1}^{\frac{1}{4}} \frac{\cos \pi \sqrt{t}}{\sqrt{t}} \; dt

stanners
May25-07, 12:05 AM
Yeah, but integration by parts didn't work, and I don't see how I can use substitution, any help?

Reshma
May25-07, 12:11 AM
The change of variable method is correct.
Put u = \sqrt t
2du = \frac{dt}{\sqrt t}
Substituting this will simplify the integrand. However, I think the mistake you are making is; you are forgetting to change the limits(1 & 1/4) of the integral. Whenever you make a variable change, the limits change according to the new variable.

Hope this helps...

tronter
May25-07, 12:11 AM
multiply numerator and denominator by \sqrt{t}

You get: \int_{1}^{\frac{1}{4}} \frac{\cos \pi t}{t} \; dt

trajan22
May25-07, 12:14 AM
A substitution should work, try u=pi(t)^.5

Reshma
May25-07, 12:19 AM
You want
\int_{1}^{\frac{1}{4}} \frac{\cos \pi \sqrt t}{\sqrt t}dt

multiply numerator and denominator by \sqrt{t}

You get: \int_{1}^{\frac{1}{4}} \frac{\cos \pi t}{t} \; dt

Hey, that's wrong :surprised. Multiplying \sqrt t in the numerator doesn't change \cos \pi \sqrt t to \cos \pi t.

stanners
May25-07, 01:01 AM
A substitution should work, try u=pi(t)^.5

Oh wow... haha, yeah.. thanks.

I was using u = cos pi(t)^.5

Bah, thanks.