View Full Version : A fermionic 2-state system
Urvabara
Jul19-07, 07:28 AM
1. The problem statement, all variables and given/known data
A fermionic 2-state system is \left\{\left|00\right\rangle, \left|10\right\rangle, \left|01\right\rangle, \left|11\right\rangle\right\}, where
\left|ab\right\rangle = \left|a\right\rangle_{1}\left|b\right\rangle_{2} and \left\langle ab\left|cd\right\rangle = \delta_{ac}\delta_{bd}.
2. Relevant equations
What are the creation and annihilation operators f_{1}, f_{1}^{\dagger}, f_{2}, f_{2}^{\dagger} in this base?
3. The attempt at a solution
I just do not know, how to get started. I just cannot find the theory and I do not know how to use it in this problem anyway. Can you give me some hints? Please, do not give right away the correct answers/results, just the hints to get started.
Gokul43201
Jul19-07, 08:10 AM
How would you find the matrix elements <ab|f|cd> of an operator f?
Urvabara
Jul19-07, 11:24 AM
How would you find the matrix elements <ab|f|cd> of an operator f?
So, I tried to calculate the matrix elements of an annihilation operator f_{1}. There are 16 of them, I think. Is this correct?
\left\langle 00\left|f_{1}\left|10\right\rangle = \left\langle 00\left|00\right\rangle = \delta_{00}\delta_{00} = 1\cdot 1 = 1.
\left\langle 00\left|f_{1}\left|01\right\rangle = 0.
\left\langle 00\left|f_{1}\left|11\right\rangle = \left\langle 00\left|01\right\rangle = \delta_{00}\delta_{01} = 1\cdot 0 = 0.
\left\langle 00\left|f_{1}\left|00\right\rangle = 0.
\left\langle 10\left|f_{1}\left|10\right\rangle = \left\langle 10\left|00\right\rangle = \delta_{10}\delta_{00} = 0\cdot 1 = 0.
\left\langle 10\left|f_{1}\left|01\right\rangle = 0.
\left\langle 10\left|f_{1}\left|11\right\rangle = \left\langle 10\left|01\right\rangle = \delta_{10}\delta_{01} = 0\cdot 0 = 0.
\left\langle 10\left|f_{1}\left|00\right\rangle = 0.
\left\langle 01\left|f_{1}\left|10\right\rangle = \left\langle 01\left|00\right\rangle = \delta_{00}\delta_{10} = 1\cdot 0 = 0.
\left\langle 01\left|f_{1}\left|01\right\rangle = 0.
\left\langle 01\left|f_{1}\left|11\right\rangle = \left\langle 01\left|01\right\rangle = \delta_{00}\delta_{11} = 1\cdot 1 = 1.
\left\langle 01\left|f_{1}\left|00\right\rangle = 0.
\left\langle 11\left|f_{1}\left|10\right\rangle = \left\langle 11\left|00\right\rangle = \delta_{10}\delta_{10} = 0\cdot 0 = 0.
\left\langle 11\left|f_{1}\left|01\right\rangle = 0.
\left\langle 11\left|f_{1}\left|11\right\rangle = \left\langle 11\left|01\right\rangle = \delta_{10}\delta_{11} = 0\cdot 1 = 0.
\left\langle 11\left|f_{1}\left|00\right\rangle = 0.
So,
f_{1} =
\begin{pmatrix}
1 & 0 & 0 & 0 \\
0 & 0 & 0 & 0 \\
0 & 0 & 1 & 0 \\
0 & 0 & 0 & 0 \\
\end{pmatrix}?
Gokul43201
Jul21-07, 09:19 AM
You've determined the non-zero matrix elements correctly, but put them in the wrong positions. The row and column indices come from the left side of those equations. Also, you haven't determined possible normalization constants.
f_1|11 \rangle = c |01 \rangle
What is c?
Urvabara
Jul21-07, 02:46 PM
You've determined the non-zero matrix elements correctly, but put them in the wrong positions. The row and column indices come from the left side of those equations.
So, something like this
f_{1} = \begin{pmatrix}0 & 1 & 0 & 0 \\0 & 0 & 0 & 0 \\0 & 0 & 0 & 1 \\0 & 0 & 0 & 0 \\\end{pmatrix}?
Also, you haven't determined possible normalization constants.
f_1|11 \rangle = c |01 \rangle
What is c?
Hmm. I have no idea. Can you give a hint?
Gokul43201
Jul21-07, 03:08 PM
So, something like this
f_{1} = \begin{pmatrix}0 & 1 & 0 & 0 \\0 & 0 & 0 & 0 \\0 & 0 & 0 & 1 \\0 & 0 & 0 & 0 \\\end{pmatrix}? Yes, that looks better.
Hmm. I have no idea. Can you give a hint?Have you come across the number operator (e.g., n_1=f_1^{\dagger}f_1)?
Urvabara
Jul21-07, 04:07 PM
Hi and thanks!
Yes, that looks better.
Have you come across the number operator (e.g., n_1=f_1^{\dagger}f_1)?
Yes, I think so. It gives the number of particles in the ground state. Right?
olgranpappy
Jul21-07, 05:13 PM
Also, n.b., this is not a two-state system.
Urvabara
Jul22-07, 01:36 AM
Also, n.b., this is not a two-state system.
Hmm. It is not? Oh boy. This was a exam problem. I failed badly in that exam. :confused:
olgranpappy
Jul22-07, 05:13 AM
well, there are four states, |00>, |01>, |10>, |11>... So it's a four-state system.
olgranpappy
Jul22-07, 05:13 AM
...two times two-states.
Gokul43201
Jul22-07, 09:27 AM
I think the original question may have called it a "2-site" problem.
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