How Do You Calculate the Length of a Spaceship Using Relativity?

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Homework Help Overview

The discussion revolves around calculating the length of a spaceship using principles of relativity, specifically focusing on two spaceships traveling in opposite directions at a significant relative speed. Participants are exploring how time and length measurements differ between reference frames due to relativistic effects.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of the Lorentz transformations and the implications of relative motion on length measurements. There are attempts to calculate the lengths of the spaceships from different frames of reference, with questions about proper length versus contracted length arising.

Discussion Status

The discussion is active, with participants sharing their calculations and questioning the assumptions behind length measurements in different frames. Some guidance has been offered regarding the expected outcomes of measurements, but there is no explicit consensus on the correct interpretation of the results.

Contextual Notes

There is some confusion regarding the proper length of the second ship and how it relates to the measurements taken from the first ship's frame. Participants are grappling with the concepts of length contraction and proper length, indicating a need for clarification on these relativistic principles.

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Homework Statement


2 spaceships traveling in opposite directions pass one another at a relative speed of 1.25x18^8 m/s. The clock on one spaceship records a time duration of 9.1x10^-8 seconds for it to pass from the front end to the tail end of the other ship. What is the length of the second ship as measured from its own rest frame?

Homework Equations


lorentz transformations

The Attempt at a Solution


Okay so I am guessing that the second ship, as measured from its rest frame should be smaller that measured from the frame of the other ship.
I used the basic equation v=x/t and plugged in my relative speed of 1.25x10^8 m/s and my time 9.1x10^-8 s. I got 11.38 m as the length measured by the first ship. Then I used the lorentz transformation for length and found the length of the second ship to be 10.34 m.
 
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tacosareveryyum said:

Homework Statement


2 spaceships traveling in opposite directions pass one another at a relative speed of 1.25x18^8 m/s. The clock on one spaceship records a time duration of 9.1x10^-8 seconds for it to pass from the front end to the tail end of the other ship. What is the length of the second ship as measured from its own rest frame?

Homework Equations


lorentz transformations

The Attempt at a Solution


Okay so I am guessing that the second ship, as measured from its rest frame should be smaller that measured from the frame of the other ship.
Should it? Who measures the proper length and who measures the contracted length?
I used the basic equation v=x/t and plugged in my relative speed of 1.25x10^8 m/s and my time 9.1x10^-8 s. I got 11.38 m as the length measured by the first ship.
This is correct.
 
tacosareveryyum said:
I used the basic equation v=x/t and plugged in my relative speed of 1.25x10^8 m/s and my time 9.1x10^-8 s. I got 11.38 m as the length measured by the first ship.
Good. This is the length of the moving ship 2 as measured by ship 1.
Then I used the lorentz transformation for length and found the length of the second ship to be 10.34 m.
How did you do this? Do moving objects measure to be shorter or longer compared to their rest lengths?

Oops: Gokul43201 beat me!
 
Okay, I am going in circles here. Isn't a measurement of length of the moving second ship going to yield a shorter length than the measurement made in the frame of the ship.
 
Okay so the second ship should be measured to be 12.50 m as measured in its own rest frame.
 
tacosareveryyum said:
Okay, I am going in circles here. Isn't a measurement of length of the moving second ship going to yield a shorter length than the measurement made in the frame of the ship.
Exactly.

tacosareveryyum said:
Okay so the second ship should be measured to be 12.50 m as measured in its own rest frame.
Much better.
 
thanks!
 

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