redox with 3 half reactions

[fish]

KBrO2 + KI + HBr ---> KBr + I2 + H2O

eq1
KBrO2 ---> KBr
4e- + 4H+ +KBrO2 ---> KBr + 2H2O

eq2
2KI ---> I2 + 2K+ + 2e-
4KI ---> 2I2 + 4K+ + 4e-

eq3
HBr ---> KBr
K+ + HBr ---> KBr + H+

since the charges in eq3 are +1=+1
you don't have to multiply this equation by 4 do you?

3H+ + KBrO2 + 4KI + HBr ---> 2KBr + 2H2O + 2I2 + 3K+


Haven't been able to find any examples or problems with
redox using 3 half reactions in any of my text books. Why
wouldn't they put a few in there?

[fish]

eq3
HBr ---> KBr
K+ + HBr ---> KBr + H+

multiply eq3 by 4 so K+ will cancel

4K+ + 4HBr ---> 4KBr + 4H+

adding all three:

KBrO2 + 4KI + 4HBr ---> 5KBr + 2H2O + 2I2