Homework Help: Find Power Used by 60 Watt Bulb Connected to 120VAC

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Discussion Overview

The discussion revolves around a homework question regarding the power used by a 60 Watt incandescent bulb connected to a 120 VAC source, specifically focusing on the relationship between voltage, resistance, and power calculations. The scope includes mathematical reasoning and conceptual clarification related to electrical power in circuits.

Discussion Character

  • Homework-related, Mathematical reasoning, Conceptual clarification

Main Points Raised

  • One participant suggests using the equation P = V squared divided by R to calculate power, arriving at 60 W.
  • Another participant agrees with the calculation, affirming that the power being used is indeed 60 W.
  • A later reply clarifies that to find average power, the rms voltage should be used instead of peak voltage, introducing the concept of v_{rms} and its relation to average power.
  • Participants express uncertainty about whether the question is a trick question, given the provided data.
  • One participant speculates that the teacher may be testing students' attention to detail in the question.

Areas of Agreement / Disagreement

Participants generally agree that the power used by the bulb is 60 W based on the given resistance and voltage, but there is some uncertainty about the nature of the question and whether it is intended to be straightforward or trickier.

Contextual Notes

There is a reliance on the definitions of rms and peak voltage, and the discussion does not resolve whether the question's intent is straightforward or if it contains an underlying complexity.

Nymn
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Sorry if this is the wrong forum, it's a homework question I'm stuck on, though. :|

The question is that if a 60 Watt bulb has a hot resistance of 240 ohms when it's connected to a 120 VAC source, how much power is the bulb using?

Now I'm not exactly sure what equation to use, I thought it would be P = V squared divided by R? That just gives me 60 W, though. What equation do I use to get the power used?
 
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looks right to me. power being used is V^2/R = 60W.

Did you post the question exactly as it is written?
 
Yah, that's pretty much how it's written. Here's the exact question:

A 60 Watt incandescent bulb has a "hot" resistance of 240 ohms when connected to a 120 VACrms source. How much power is the light bulb using?

So...the answer is 60 Watts, then? Is it a trick question? o_O
 
Oh wait... in order to get average power, you need to use rms voltage, not peak voltage.

[tex]v_{rms} = \frac{v_{peak}}{\sqrt{2}}[/tex]

then use average power = [tex]\frac{(v_{rms})^2}{r}[/tex]
 
Oh crap. sorry again... so they give you 120V rms not 120peak...

So then 60W is the answer. hmmm... strange question...
 
Maybe my teacher is checking to see if we're paying attention. :P
 

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