silimay
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Sorry... my message got posted by mistake before I started typing. Here is what I was going to say:
I'm having a problem just understanding something from my quantum book. They're deriving something to do with a wave packet with the Schrödinger equation, and they have the equation of a wave packet at time t = 0:
[tex]\psi(x,0) = \int_{- \infty}^{+ \infty} dk A(k) e^{i(kx)[/tex]
where [tex]A(k) = e^{- \alpha (k - k_o)^2 / 2}[/tex]
They change variables to [tex]q' = k - k_o[/tex] and then they get
[tex]\psi(x,0) = e^{i k_o x} e^{- x^2 / {2 \alpha}} \int_{- \infty}^{+ \infty} dq' e^{- \alpha {q'}^2 / 2}[/tex]
I don't understand how they got that (specifically, the [tex]e^{-x^2 / {2 \alpha}}[/tex] term).
I'm having a problem just understanding something from my quantum book. They're deriving something to do with a wave packet with the Schrödinger equation, and they have the equation of a wave packet at time t = 0:
[tex]\psi(x,0) = \int_{- \infty}^{+ \infty} dk A(k) e^{i(kx)[/tex]
where [tex]A(k) = e^{- \alpha (k - k_o)^2 / 2}[/tex]
They change variables to [tex]q' = k - k_o[/tex] and then they get
[tex]\psi(x,0) = e^{i k_o x} e^{- x^2 / {2 \alpha}} \int_{- \infty}^{+ \infty} dq' e^{- \alpha {q'}^2 / 2}[/tex]
I don't understand how they got that (specifically, the [tex]e^{-x^2 / {2 \alpha}}[/tex] term).
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