A pretty difficult problem about oscillatory circuit

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SUMMARY

The discussion centers on solving a problem related to oscillatory circuits using differential equations. Key equations include the relationship between voltage, current, and inductance, specifically \(\epsilon = L_{1}\frac{dI}{dt}\) and \(\epsilon_{c} = -L_{2}\frac{dI}{dt}\). The circuit parameters and their interactions are crucial for understanding the behavior of the oscillatory circuit. The solution involves analyzing the equation \(IR + \frac{q}{C} = \frac{dI}{dt}(L_{1} - L_{2})\).

PREREQUISITES
  • Understanding of LC circuits and their properties
  • Familiarity with differential equations
  • Knowledge of circuit components: inductors (L), capacitors (C), and resistors (R)
  • Ability to interpret circuit diagrams and equations
NEXT STEPS
  • Study the behavior of LC circuits in depth
  • Learn how to solve differential equations related to electrical circuits
  • Explore the implications of circuit parameters on oscillation frequency
  • Investigate the use of simulation tools for circuit analysis, such as LTspice
USEFUL FOR

Electrical engineering students, circuit designers, and anyone interested in the dynamics of oscillatory circuits and their mathematical modeling.

Sciencelad
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An oscillatory circuit

Homework Statement


So, there are parameters of a circuit. Also we got an answer. Just look at image below in the attachments.


Homework Equations


This problem uses simple differential equations. All I could write down here is on the wikipedia page: http://en.wikipedia.org/wiki/LC_circuit"


The Attempt at a Solution


After some pondering, I've got something about that.
[tex]\epsilon=L_{1}\frac{dI}{dt}[/tex]
[tex]\epsilon_{c}=-L_{2}\frac{dI}{dt}[/tex]
[tex]U=I*R[/tex]
[tex]U\epsilon_{c}=\frac{q}{C}[/tex]
So that:
[tex]IR+\frac{q}{c}=\frac{dI}{dt}(L_{1}-L_{2})[/tex]
 

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