View Full Version : Differentiation dilemma
disfused_3289
Dec19-07, 07:47 AM
I'm having trouble with the following questions about differention with respect to x.
Differentiate with respect to x:
a)
y= 2/ (2x+3)^4
b)
y= x(x+1)^(1/2)
c)
y= (x +1)(x^2 + 3x)^3
d)
y= 3x^3 + 3x^(-1/2) + 2
Any help would be greatful
Have you learned the chain rule yet?
Hootenanny
Dec19-07, 07:57 AM
a) y= 2/ (2x+3)^4
Re-write as;
y = 2(2x+3)^{-4}
And use the chain rule.
b)y= x(x+1)^(1/2)
c)y= (x +1)(x^2 + 3x)^3
Chain rule and product rule
d) y = 3x^3 + 3x^(-1/2) + 2
Just use the power rule.
disfused_3289
Dec19-07, 07:57 AM
Yes, I have learnt chain rule
to differentiate from x you find dy/dx
disfused_3289
Dec19-07, 08:05 AM
Here are my solutions, I don;t know if they're correct
a)
y= 2/ (2x+3)^4
= -4(2x +5)^(-5) x 2 x 2
= -16/ (2x + 5) ^ (-5)
b)
y= x(x+1)^(1/2)
= ( x + 2) (x + 1)^ (1/2) / 2
d)
y = 3x^3 + 3x^(-1/2) + 2
= 3x^2 - 3/2x^(1/3)
Hootenanny
Dec19-07, 08:11 AM
Here are my solutions, I don;t know if they're correct
a)
y= 2/ (2x+3)^4
= -4(2x +5)^(-5) x 2 x 2
= -16/ (2x + 5) ^ (-5)
Almost, where's the +5 come from in the bracket? And are you sure that should be a -5?
b)
y= x(x+1)^(1/2)
= ( x + 2) (x + 1)^ (1/2) / 2
I'm not sure where your coming from with that, perhaps if you posted your steps?
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